Ha. Trick question! All of them are already full of air, and niether the flow rate nor the direction (or lack) of gravity was specified anyway. You lose. :)
this post was submitted on 30 Nov 2024
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OH İTS THE FUCKİNG LOSS COMİC
- 5 which begins to overflow into the room
- 7
- 4 and 6
- 2 and 3
- 1
This is assuming this is a cross section of something 3d and not something 2d otherwise air packets would get trapped and prevent some of this.
5 and 4 are the only ones getting water other than 1 and 2. 3 has a solid line blocking the flow into it, and even if that wasn't there, since 4 has a hole/drain in the bottom and 5 can overflow, 3 can't fill enough to reach the outflow. 5 is the only one that can fill up.
5
Also, you suck.
Depends on how fast the liquid is flowing in.
Or, actually, can they even "fill"? These are 2D objects.
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5, but it also depends on the circumstances. What liquid is used, temperature, viscosity, etc. There's some material science stuff that's far beyond the intended scope of this question.
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I hate you so much right now. Also I think it's 5
It's only 5. It just overflows.
Depends on the flow from the faucet.
If it is filling 1 faster then water can move between then order will be 1->2->5
If it is slow enough then just 5 fills.
Everything else will be dry. Between 2 to 3 is sealed too. Without lids there is a lot of issues.
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Yeah nothing will fill up until 5 is full. And then since 4 has a leak it, I think basically ONLY 5 will fill.
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None. The water is not running.
All the candidates are thanked for their time and asked to leave except you, who get invited to join MIB.
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All I know is, 7 is leaking out.
Dude, so dark… I love it.
Unless I completely misunderstand how this works, I think 5 is the only one that will fill up. It then overflows, preventing any of the taller ones from filling. 7 is shallower but won't start filling until 3 gets fuller than 5, which it never will. This would be true whether the blockage between 2 and 3 is a mistake or not.
You are correct and I agree, but look again.
At the comments.
Then at the image.
Forget all about the water, and the question.
If necessary, reread the title.
Groan.
Please help. I have nightmares of being in a room where everyone else is just waiting patiently for me to remember the thing I forgot/figure out what is happening.
Help
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I think you’re right. Unfortunately, we’ll still have to chalk this up as a loss.
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Depends on how much you turn on the tap. If you fürn it up completely its 1,else its 5.
Depends on diameter of the pipes leading out too. They look small in the image, but if they're big enough to handle the max flow out of the faucet, 5 will still fill up first.
They are all full already, of air.
5
Wait... Fuck!
this is right. Even if 2 to 3 is open.
The only other candidate is 1. If the faucet has much higher flow than the pipe from 1 to 2 can drain away, then 1 can fill up faster than it drains.
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1 fills up first. the spigot is much winder than the tube so the glass will fill faster than it can drain.
Also rule
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I actually started to figure out the sequence...then I realized...fuck you, take my up vote
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5 will be the only one that will ever fill up unless you really crank up the pressure in which case 7 will also fill but very slowly. 5 and 7 are open containers and there's a hole in the bottom of 4. But if it's water coming out of a tap then only 5 will fill .
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i hate you.
edit: read replies before telling me that 7 is walled off
but ignoring my loss, if everything is pressurized i think 7 if unpressurized i think 5
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Wouldn't scale and viscosity play a role? Seriously, imagine a river vs a capillary tube. Also how many dimensions? And forces involved? Is that a blockage between 2 and 3? Are the walls breakable? How will the fluid hold air? Are the lines into structure 5 lower than the walls? Is this in a vacuum?
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5
I wish these were drawn as closed containers
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