this post was submitted on 28 Aug 2024
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Can't tell if that's a genuine answer or a joke sooo...
They're moving perpendicular so unfortunately it's not that easy... I'll leave the calculations to someone who didn't fail math though
Oh that makes sense why the elapsed time would factor into the equation too.
To trick you.
Now if the question had been something like:
Then you'd need differential equations or whatever the class is, and you'd have to use more than just basic trig, but as written, it's just basic trig and the time is irrelevant.
The time matters because the angle is changing and with it the relative velocity.
No, the angle is never changing.
I just drew a picture and you're right, the triangle has the same angles, the sides just get longer.
But the speed they are moving apart from each other is increasing. Edit: IDK LOL but if you drew it as a triangle the long side would be getting longer and longer, in the first second it might grow a little bit but after some time in one second it would grow a lot. If you need anymore physics questions examined please let me know
Wouldn't that be just a right triangle? One side 5×5=25 feet long, the other 5×1=5 feet long so the hypotenuse would be the square root of (25²+5²) or around 25,5 feet.
That's basic geometry right? It's been quite a few month but I'm pretty sure I still can do highschool level maths.
That's the distance yes, but how fast are they moving away from eachother
(5^2 + 1^2)^0.5 = 5.1ft/s
Well, like I said I failed math so I'll take your word for it
Edit: autocorrect fucked me