Let's do the math! If you assume there are 300 kernels, the popcorn will be finished within two minutes, and all kernels popping within 100 ms of each other is sufficient for a big bada boom...

There are 2×60×10 epochs where the bang could occur. Each of the 300 kernels needs to pop in the same epoch, so 1/(2×60×10) is the probability of the second kernel popping in the same epoch as the first kernel. The probability of all 299 popping in the same epoch as the first kernel is (1/(2×60×10))^299 = (2×60×10)^(-299).

Crunching the numbers in the Google search calculator... the probability is zero. That was anticlimactic.

[–] visnae 3 points 9 months ago

I can't imagine it would be equally distributed? Probably normal distribution applies over the span, most of the kernels would probably pop within say 20s of each other, and none in the beginning.

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