this post was submitted on 09 Jan 2024
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[–] [email protected] 37 points 1 year ago (1 children)

One equation, sure, but not in one valid function (without making it parametric anyways)

[–] NorthWestWind 3 points 1 year ago (3 children)

x^2^+y^2^=1
or, in this case
(x-2)^2^+(y-2)^2^=1

[–] SkybreakerEngineer 19 points 1 year ago

Not valid functions

[–] [email protected] 12 points 1 year ago (1 children)
[–] NorthWestWind 2 points 1 year ago

Ok you're right

[–] [email protected] 3 points 1 year ago

A that's a single equation alright. But as the previous poster pointed out, it's not a function.