Science Memes

11130 readers

3759 users here now

Welcome to c/science_memes @ Mander.xyz!

A place for majestic STEMLORD peacocking, as well as memes about the realities of working in a lab.

Rules

Don't throw mud. Behave like an intellectual and remember the human.
Keep it rooted (on topic).
No spam.
Infographics welcome, get schooled.

This is a science community. We use the Dawkins definition of meme.

Research Committee

[email protected]

Other Mander Communities

Science and Research

Biology and Life Sciences

Physical Sciences

Humanities and Social Sciences

Practical and Applied Sciences

Memes

Miscellaneous

founded 2 years ago

MODERATORS

[email protected]

916

Or we could do metric time (files.catbox.moe)

submitted 7 months ago by [email protected] to c/[email protected]

197 comments fedilink hide all child comments

you are viewing a single comment's thread
view the rest of the comments

[–] [email protected] 0 points 7 months ago (3 children)

Which breaks "day of week = day modulo 7" if every month starts on Monday and not every month has the same number of days

[–] [email protected] 13 points 7 months ago (1 children)

In this scheme, new years day and leap days are not any day of the week or part of any month. They exist outside of the regular calendar as obvious and explicit resets to the remainder problem.

[–] [email protected] 2 points 7 months ago (1 children)

My point exactly. So the programmer who commented above me is wrong in saying it makes it easier for them

[–] [email protected] 2 points 7 months ago* (last edited 7 months ago) (1 children)

No, still easier. They are still part of the year, so you can just count them, and the logic is still easier than the mess we currently have. If you really feel the need to you can call new years day the zeroth day in the zeroth month, the day of the week is Holiday, and periodically the zeroth month has one extra Holiday.

[–] [email protected] -1 points 7 months ago (1 children)

Computers store the date as "days after January 1st 1970". So you have a huge number, divide it with 7 and get the day of the week. If there are days that don't belong to any week, you have to calculate January 1st of that year and substrate it in addition to the steps above. I don't say it's not manageable, but it's not easier

[–] [email protected] 2 points 7 months ago (1 children)

They store the number of seconds since the epoch of 1970, but you're always going to have leap days and even leap seconds. Even if you changed the definition of a second to match the current length of a year, it would be off again relatively soon and you'd need leap seconds again. It's NEVER going to be as simple as you seem to think it should be. Chaos and complexity is inherent in the whole system.

[–] [email protected] 1 points 7 months ago (1 children)

I never said it was simple. The comment above me was "oh, this makes it much easier" and I was like "it's not really getting easier". That's all I said.

[–] [email protected] 1 points 7 months ago (1 children)

Yes, I understood. I still disagree for the reasons in all of my previous comments.

[–] [email protected] 0 points 7 months ago

Let's agree to disagree

[–] grue 7 points 7 months ago (1 children)

Look, short of changing Earth's orbit, something's not gonna line up no matter what you do. Extra-weekly days are as good a compromise as any in my book.

[–] [email protected] 4 points 7 months ago

There is also a technological solution, I knew it

[–] [email protected] 3 points 7 months ago (1 children)

Leap day and new year day are supposed to not be a week day in this system

[–] [email protected] -4 points 7 months ago

My point exactly. So the programmer who commented above me is wrong in saying it makes it easier for them