this post was submitted on 11 Feb 2025
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[–] [email protected] 11 points 6 hours ago (3 children)

It really doesn't make sense to start at 1 as the value is really the distance from the start and would screw up other parts of indexing and counters.

[–] IndustryStandard 4 points 6 hours ago (2 children)

It would screw up existing code but doing [array.length() -1] is pretty stupid.

[–] [email protected] 2 points 5 hours ago

A lot of languages have a .last() or negative indexer ([-1]) to get the last item though.

[–] thedeadwalking4242 3 points 6 hours ago* (last edited 1 hour ago) (1 children)

For i = 0; I < array.length; i++

[–] [email protected] 4 points 4 hours ago

i < array.length or else you overflow.

[–] Klear 3 points 5 hours ago

It doesn't make sense that the fourth element is element number 3 either.

Ultimately it's just about you being used to it.

[–] [email protected] 2 points 5 hours ago (1 children)

Yeah, but if we went back and time and changed it then there wouldn't be other stuff relying on it being 0-based.

[–] [email protected] 2 points 4 hours ago (1 children)

It was not randomly decided. Even before arrays as a language concept existed, you would just store objects in continuous memory.

To access you would do $addr+0, $addr+1 etc. The index had to be zero-based or you would simply waste the first address.

Then in languages like C that just got a little bit of syntactic sugar where the '[]' operator is a shorthand for that offset. An array is still just a memory address (i.e. a pointer).

[–] [email protected] 1 points 2 hours ago

I know. But in the alternate reality where we'd been using 1-based indices forever you'd be telling me how useful it is that the first element is "1" instead of zero and I'd be saying there are some benefits to using zero based index because it's more like an offset than an index.