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Code interviews for a PHP developer roles (reddthat.com)

submitted 8 months ago by [email protected] to c/linuxmemes

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[–] [email protected] 40 points 8 months ago (1 children)

Want to print out all odd numbers from 1 to 100? Easy:

for(_=[];_<+!![]+""+[]*[]+[]*[];_++)(_%+(!![]+!![])?console.log(_):[]);

[–] [email protected] 17 points 8 months ago (1 children)

Actually, I prefer this one: for(_=[];_<+!![]+""+[]*[]+[]*[];_++%+(!![]+!![])?[]:console.log(_));

[–] [email protected] 18 points 8 months ago (1 children)

Or this one without the "undefined" when run in a browser console:

for(_=[];_<+!![]+""+[]*[]+[]*[]-!![]-!![];_++%+(!![]+!![])?[]:console.log(_));_+!![]

[–] [email protected] 2 points 8 months ago (1 children)

Wtf people, can somebody explain?

[–] [email protected] 2 points 8 months ago

_ is a variable name, [] becomes 0 when converted to an integer, !![] becomes 1. The + "" + means that the integers 1, 0, 0 get converted to a string - "100", which gets converted back to an integer because it's in the for loop. And there's various other horrible conversions going on to make it all work.