this post was submitted on 01 Dec 2023
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2023

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[โ€“] [email protected] 2 points 11 months ago (1 children)

I just solved it. I printed every set of integers in the format "Result: [theTwoDigits], from string: [inputString]" and mannually checked all of them. Eventually found the edge case that was causing troubles. It was a typo.

[โ€“] [email protected] 3 points 11 months ago (1 children)

Oh god, sorry to hear that ๐Ÿ˜…i'm feeling desperate enough to try that, i just wrote a different implementation and i get the same (wrong) result. At this point I just want to know what i misunderstood or mistyped cuz its driving me crazy

[โ€“] [email protected] 2 points 11 months ago (1 children)

The bug is some strings can have overlapping characters. onEight threEight fivEight. There are more cases. So if you do a search and replace your string becomes 1ight 3ight and the second number does not get found.

Possible fixes: Search and replace and add the extra letter: oneEigh then search and replace. Search and replace words to numbers but put some extra letters in just in case.

[โ€“] [email protected] 1 points 11 months ago

Thanks, I managed to find the culprit in the end however - I was using a forward-look of 5 characters for finding if it matches a word so in a string of a3two for example, it would register the two before the 3. It was an easy fix once i found the issue.