this post was submitted on 25 Nov 2023
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[–] [email protected] 14 points 1 year ago (2 children)

The real problem with the way Spotify distributes the money, is that they distribute it per play. This seems reasonable on the surface, but I think it's pretty shit. I want my subscription fee to go to the artists I listen to. Right now they're going to what most people listen to. This effect is worsened by the per-label deals: imagine if Beyonce wasn't on Spotify, that would be bad for Spotify right? This gives her label (and by extension all major labels) massive leverage over how this works. It massively favors big artists.

The per-play model also enables playfarming as an economically viable scam.

[–] [email protected] 2 points 1 year ago (2 children)

Huh? If you listen to obscure music, they are paid for that, if you don't they don't. They base it of what people listen to, in the exact same way it would work if it was watermarked like you want it to be

[–] [email protected] 1 points 1 year ago

No it wouldn't. Imagine a hyper-small version of Spotify with two artists and two subscribers. The fee is 10$ per user, distributed fully to the artists (to make the math easy).

User A only listens to artist A, user B only listens to artist B. BUT: user A listens to artist A 30 times a month, while user b only listens to artist B 10 times a month. Artist A gets paid 15 of the 20 total dollars - user B is paying for some of artist A's fee, even though they've never listened to them.

My Spotify subscription is paying for the artists most put on large playlists, the ones most played by fitness centers and cafes, and for botfarms. I want it to pay the artists I listen to.

[–] [email protected] 1 points 1 year ago

While sure, there is leverage, but it's not like Spotify is being arbitrary about their content. I can listen to obscure stuff, and I do. Also don't forget that big artists are often big for a reason and it's usually not for a lack of talent, taste just varies but certainly there always is a market for 'pop music'.