Haskell
Abused ParserCombinators
for the first part. For the second, I took quite a while to figure out dynamic programming in Haskell.
Solution
module Day12 where
import Data.Array
import Data.Char (isDigit)
import Data.List ((!!))
import Relude hiding (get, many)
import Relude.Unsafe (read)
import Text.ParserCombinators.ReadP
type Spring = (String, [Int])
type Problem = [Spring]
parseStatus :: ReadP Char
parseStatus = choice $ char <$> ".#?"
parseSpring :: ReadP Spring
parseSpring = do
status <- many1 parseStatus <* char ' '
listFailed <- (read <$> munch1 isDigit) `sepBy` char ','
return (status, listFailed)
parseProblem :: ReadP Problem
parseProblem = parseSpring `sepBy` char '\n'
parse :: ByteString -> Maybe Problem
parse = fmap fst . viaNonEmpty last . readP_to_S parseProblem . decodeUtf8
good :: ReadP ()
good = choice [char '.', char '?'] $> ()
bad :: ReadP ()
bad = choice [char '#', char '?'] $> ()
buildParser :: [Int] -> ReadP ()
buildParser l = do
_ <- many good
sequenceA_ $ intersperse (many1 good) [count x bad | x <- l]
_ <- many good <* eof
return ()
combinations :: Spring -> Int
combinations (s, l) = length $ readP_to_S (buildParser l) s
part1, part2 :: Problem -> Int
part1 = sum . fmap combinations
part2 = sum . fmap (combinations' . toSpring' . bimap (join . intersperse "?" . replicate 5) (join . replicate 5))
run1, run2 :: FilePath -> IO Int
run1 f = readFileBS f >>= maybe (fail "parse error") (return . part1) . parse
run2 f = readFileBS f >>= maybe (fail "parse error") (return . part2) . parse
data Status = Good | Bad | Unknown deriving (Eq, Show)
type Spring' = ([Status], [Int])
type Problem' = [Spring']
toSpring' :: Spring -> Spring'
toSpring' (s, l) = (fmap toStatus s, l)
where
toStatus :: Char -> Status
toStatus '.' = Good
toStatus '#' = Bad
toStatus '?' = Unknown
toStatus _ = error "impossible"
isGood, isBad :: Status -> Bool
isGood Bad = False
isGood _ = True
isBad Good = False
isBad _ = True
combinations' :: Spring' -> Int
combinations' (s, l) = t ! (0, 0)
where
n = length s
m = length l
t = listArray ((0, 0), (n, m)) [f i j | i <- [0 .. n], j <- [0 .. m]]
f :: Int -> Int -> Int
f n' m'
| n' >= n = if m' >= m then 1 else 0
| v == Unknown = tGood + tBad
| v == Good = tGood
| v == Bad = tBad
| otherwise = error "impossible"
where
v = s !! n'
x = l !! m'
ss = drop n' s
(bads, rest) = splitAt x ss
badsDelimited = maybe True isGood (viaNonEmpty head rest)
off = if null rest then 0 else 1
tGood = t ! (n' + 1, m')
tBad =
if m' + 1 <= m && length bads == x && all isBad bads && badsDelimited
then t ! (n' + x + off, m' + 1)
else 0
Haskell
Managed to do part1 in one line using ByteString operations:
Part 2