I was surprised seeing ton of people going for the replace approach. It didn't even cross my mind to edit the string, I went straight for regex for part 1 and it was easy enough to adapt it for part 2.
Advent Of Code
An unofficial home for the advent of code community on programming.dev!
Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.
AoC 2024
Solution Threads
M | T | W | T | F | S | S |
---|---|---|---|---|---|---|
1 | ||||||
2 | 3 | 4 | 5 | 6 | 7 | 8 |
9 | 10 | 11 | 12 | 13 | 14 | 15 |
16 | 17 | 18 | 18 | 20 | 21 | 22 |
23 | 24 | 25 |
Rules/Guidelines
- Follow the programming.dev instance rules
- Keep all content related to advent of code in some way
- If what youre posting relates to a day, put in brackets the year and then day number in front of the post title (e.g. [2024 Day 10])
- When an event is running, keep solutions in the solution megathread to avoid the community getting spammed with posts
Relevant Communities
Relevant Links
Credits
Icon base by Lorc under CC BY 3.0 with modifications to add a gradient
console.log('Hello World')
On the surface level it makes sense since you already wrote the code to extract the numbers based on digits, which will be in the back of your mind. Once you have some time think about though, it's obvious it's better to just directly find the first and last "digit" without changing the string.
I did this exact thing and hit the point where it didn't work. I appreciated that the problem broke my code because it made me arrive at a better solution.
My solution was worse than most: replace one -> one1one You are only going to do the replace all for each number and if the "e" is also in eight it is still there for the next set of replace.
A better quick and dirty solution from Mastodon was to just add the common character first: twone -> twoone
I just check every substring haha
That's an esthetic abomination, but very clever
I have a friend who says that "whatever works is elegant" and solutions like OP's is why I simultaneously love and hate that phrase.
Behold, elegance:
digits = { "one": [1,2], "two": [2,2], "three": [3,4], "four": [4,3], "five": [5,3], "six": [6,2], "seven": [7,4], "eight": [8,4], "nine": [9,3], "1": [1,1], "2": [2,1], "3": [3,1], "4": [4,1], "5": [5,1], "6": [6,1], "7": [7,1], "8": [8,1], "9": [9,1] }
and what comes afterwards is even more elegant, for it works!
The problem is that 21 is not the only problematic combination.
You can also use o1e as there are never more than a single shared character. It also doesn't change the string size so it can be done in place. Still an ugly hack of a solution.
I have hacked together the ugliest of solutions and got my two stars but at what price?
I just reverse the string and reverse the number names >_>
Cheater?
Maybe...
That's clever. Way more than my Regex abomination
everything
Just saw this community and it looks cool even though I'm probably not capable of solving most of the puzzles. But having looked through the community, I can only really find solution threads. Where are the actual puzzles posted so I can give it a go?
https://adventofcode.com/2023 The first question is public, login to get your test data and submit your answers and unlock part 2.
But I don't wanna log in, though. I don't care about the leaderboards or anything like that, and call me old fashioned, but I don't like giving my identity to every little website I visit as a matter of general principles.
There is an anon mode, but it does want you to log in to keep track of progress, either through Google, GitHub etc. I do wish there was a true logless mode but I think it's cool enough for me to just want to do