this post was submitted on 22 Oct 2023
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Programmer Humor

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[–] [email protected] 4 points 1 year ago (1 children)

Last one should be // still a student

[–] [email protected] 4 points 1 year ago

Every single entry other than thief is "still a student"

[–] [email protected] 4 points 1 year ago (1 children)

@coja I am the engineer because I forget about Math.max existence

[–] [email protected] 4 points 1 year ago

Engineer likely ends up with the smallest code. Though the hit to execution time for a branch sucks. (Pipelines and such)

Bit hacker will take the least execution time because of pipelines, but it needs more comments. Maybe something like // trust me, this works.

[–] AlmightySnoo 4 points 1 year ago* (last edited 1 year ago) (1 children)

What about the smooth approximation nerd?

import math
def max12(x, y, alpha=10):
  u = math.exp(alpha * x)
  v = math.exp(alpha * y)
  return (u * x + v * y) / (u + v)

(obviously beware of overflows)

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[–] Windex007 4 points 1 year ago

I use 8, but only when I'm operating on unsigned longs.

[–] affiliate 3 points 1 year ago

here’s another mathematical approach (that has the added benefit of only working when x and y are both positive).

let f denote the linear functional on ℝ^2^ defined by f(1,0) = x and f(0,1) = y (and extend by linearity). then the operator norm || f || is equal to max(x,y).

[–] [email protected] 3 points 1 year ago

I'm mostly lost and in over my head

[–] [email protected] 3 points 1 year ago

Yoink.

Actually I've probably been all of these at various times in my career.

[–] [email protected] 2 points 1 year ago

Why use const max = (x, y) => x > y ? x : y instead of function max(x, y) { return x > y ? x : y } ?

[–] dinckelman 2 points 1 year ago (2 children)

2, but I'm incredibly embarrassed to say that I've had to do 9 before

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[–] [email protected] 1 points 1 year ago* (last edited 1 year ago)

my $max = $x > $y ? $x : $y;

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