this post was submitted on 01 Dec 2023
17 points (100.0% liked)

NotAwfulTech

337 readers
1 users here now

a community for posting cool tech news you don’t want to sneer at

non-awfulness of tech is not required or else we wouldn’t have any posts

founded 1 year ago
MODERATORS
[email protected]
17
The official awful.systems Advent of Code 2023 thread (awful.systems)
submitted 9 months ago* (last edited 9 months ago) by [email protected] to c/[email protected]
121 comments fedilink hide all child comments
 

Rules: no spoilers.

The other rules are made up as we go along.

Share code by link to a forge, home page, pastebin (Eric Wastl has one here) or code section in a comment.

you are viewing a single comment's thread
view the rest of the comments
[–] [email protected] 3 points 9 months ago (2 children)

spoilerPart 2 only, but Part 1 is very similar.

#!/usr/bin/env jq -n -R -f
[
  # For each line, get numbers eg: [ [1,2,3] ]
  inputs / " " | map(tonumber) | [ . ] |

  # Until latest row is all zeroes
  until (.[-1] | [ .[] == 0] | all;
   . += [
     # Add next row, where for element(i) = prev(i+1) - prev(i)
     [ .[-1][1:] , .[-1][0:-1] ] | transpose | map(.[0] - .[1])
    ]
  )
  # Get extrapolated previous element for first row
  |  [ .[][0] ] | reverse | reduce .[] as $i (0; $i - . )
]

# Output sum of extapolations for all lines
| add

I'm pretty sure you could make this one line and unreadable ^^.

[–] [email protected] 3 points 9 months ago

Here's where I landed in dart

no comments

d9(bool s) {
  print(getLines().fold(0, (p, e) {
    int pre(List h, bool s) {
      return h.every((e) => e == 0)
          ? 0
          : (pre(List.generate(h.length - 1, (i) => h[i + 1] - h[i]), s)) *
                  (s ? -1 : 1) +
              (s ? h.first : h.last);
    }

    return p + pre(stois(e), s);
  }));
}

[–] [email protected] 3 points 9 months ago

Now this is content