this post was submitted on 02 Nov 2023
108 points (99.1% liked)

Technology

59674 readers
4285 users here now

This is a most excellent place for technology news and articles.


Our Rules


  1. Follow the lemmy.world rules.
  2. Only tech related content.
  3. Be excellent to each another!
  4. Mod approved content bots can post up to 10 articles per day.
  5. Threads asking for personal tech support may be deleted.
  6. Politics threads may be removed.
  7. No memes allowed as posts, OK to post as comments.
  8. Only approved bots from the list below, to ask if your bot can be added please contact us.
  9. Check for duplicates before posting, duplicates may be removed

Approved Bots


founded 1 year ago
MODERATORS
 

Passkey support arrived in KeePassXC https://github.com/keepassxreboot/keepassxc/issues/1870

Just last week so it's not in any distributions yet, but a binary can be found here: https://snapshot.keepassxc.org/build-235575/

I haven't tried it yet because I haven't been using passkeys because it wasn't implemented in KeePassXC but now that it is I will try on some page which implements it. Just need to figure out who implements it. I think none of the Fediverse services does yet.

you are viewing a single comment's thread
view the rest of the comments
[–] [email protected] 2 points 1 year ago

Also no expert about the math behind it but this is how I learned asymmetric encryption with public and private key on a very high level of abstraction:

To encrypt a message you basically take the unencrypted message to the power of the private key (lets call that d) and divide it by the result of a multiplication of two large prime numbers (lets call that N). Now you take the rest of that division, so basically modulo if you are familiar with that.

To decrypt, you take the encrypted message to the power of the public key (e) and divide it by N. The rest of that operation is again the unencrypted message.

So the private and public key are the pairs (d, N) and (e, N) respectively. The great thing about this is that you can post the public key publicly without care and only you, in possession of the private key, can decrypt messages encrypted with your public key. So its easy to verify if you got the key but hard to brute force due to modulo being a one way function. However, this basic RSA approach as described here is not used on its own anymore but rather in combination with other techniques to prevent guessing on very short messages or keys.