this post was submitted on 03 Oct 2023
8 points (100.0% liked)
Ask Electronics
3173 readers
5 users here now
For questions about component-level electronic circuits, tools and equipment.
Rules
1: Be nice.
2: Be on-topic (eg: Electronic, not electrical).
3: No commercial stuff, buying, selling or valuations.
4: Be safe.
founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
Do you have a datasheet/part number for the LEDs, or at least a picture and diameter?
Because battery voltage reduces over time, the LEDs will get dimmer as the battery drains fairly quickly. If possible, running it off a mains plugpack (e.g.12V like for a router or external hard drive) would be good.
An example UV LED has a forward voltage of nominally 3.7V. Two in series on a 12 (8x1.5V) supply gives us 12V-(2x3.7V) =4.6V to drop across the resistor. We want ~15mA, so need a very roughly (V/I =R) 4.6V/0.015A=300 ohm resistor.
When the battery is nearly discharged, at 1.1V/cell it will be 8.8V, giving 1.4V across the resistor and V/R=I 1.4V/300ohm= 4.7mA.
So you would connect each pair of LEDs as:
BAT+ RES +LED- +LED- -BAT all in series. Like this.
You'll need another 10 300 ohm resistors for 15 total, one per pair of LEDs.
Its a 5mm Led
Three in series per 300 ohm resistor would be OK with those.
Thank you ao much! I'll Try!