this post was submitted on 20 Oct 2024
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Python

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[–] monica_b1998 3 points 4 weeks ago (1 children)

Good question - it's the latter: all the blocks are generated practically instantaneously, whereas it does take a noticeable amount of time for the first block to hit the next one.

if i==25 would only result in the last block falling down, the rest would remain standing.a

[–] [email protected] 3 points 4 weeks ago (1 children)

Oh that makes sense - apparently bpy.ops has a current context that the transform acts on. Instead could you move the transform call outside of the loop after establishing the first block as the context? That's how I would instinctively do it, to avoid checking i in every iteration when I know it can only be true once. Totally minor critique lol.

[–] monica_b1998 2 points 4 weeks ago

that makes sense! if I find the time, I'll update it. it needs to updated to a newer Blender version anyway....