Math Riddles
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Riddles, not homework. This community is for people to share math problems that they think others would enjoy solving. It is not intended for helping students with homework problems or explaining mathematical concepts. Posting riddles which you do not know the answer to is permitted.
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Harder than trivial. While math riddles of any difficulty are welcomed, please avoid posing problems whose solution is formulaic and/or trivial.
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Spoiler your answers. The intent here is to let others engage in discussion without giving the answer away. It's fun to think about it, and choose when you need a hint!
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Answer context: if you light both ends of one rope, the two flames will always meet each other and fizzle out in exactly 30 minutes.
Key takeaway:
So you may (correctly) think that 3 flames = ⅓ hour. But there's trick to it. Those 3 flames should always be; 2 on the end, and 1 arbitrarily in the middle.
Doing this will actually cause 1 rope segment with 3 flames to turn into 2 rope segments with 4 flames. Since that middle flame was placed arbitrarily, we can expect one of the segments to burn up before the other. When this happens, we just place a new flame arbitrarily in the middle of the remaining segment, splitting it back into 2.
As long as we keep adding flames so that we always have 2 segments, the total rope will ultimately burn in 20 minutes (⅓ hour).
This is generalizable; to achieve any fraction of 1/x hours, we need to always maintain x-1 segments (min 1). So for ½ hour, we need to maintain 1 segment. For ⅐ hour, we need to maintain 6 segments, etc.
Final answer: 25 minutes can be expressed as ⅙+¼ hours. Therefore we need to burn the first rope such that we always maintain 5 segments. Then once that's fully burnt, we just burn the second rope such that we always maintain 3 segments.