this post was submitted on 07 Dec 2023
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Advent Of Code

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Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2023

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Day 7: Camel Cards

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  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ , pastebin, or github (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)

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[โ€“] [email protected] 2 points 11 months ago (2 children)

This wasn't too bad. Had a worried moment when the part 2 solution took more than half a second. Maybe a better solution that brute forcing all the joker combinations, but it worked.

Python

import re
import argparse
import itertools
from enum import Enum

rule_jokers_enabled = False

class CardType(Enum):
    HighCard = 1
    OnePair = 2
    TwoPair = 3
    ThreeOfAKind = 4
    FullHouse = 5
    FourOfAKind = 6
    FiveOfAKind = 7

class Hand:
    def __init__(self,cards:str,bid:int) -> None:
        self.cards = cards
        self.bid = int(bid)
        if rule_jokers_enabled:
            self.type = self._find_type_joker(cards)
        else:
            self.type = self._find_type(cards)

    def _find_type(self,cards:str) -> CardType:
        # group cards based on card counts
        card_list = [*cards]
        card_list.sort()
        grouping = itertools.groupby(card_list,lambda x:x)
        lengths = [len(list(x[1])) for x in grouping]
        if 5 in lengths:
            return CardType.FiveOfAKind
        if 4 in lengths:
            return CardType.FourOfAKind
        if 3 in lengths and 2 in lengths:
            return CardType.FullHouse
        if 3 in lengths:
            return CardType.ThreeOfAKind
        if len([x for x in lengths if x == 2]) == 2:
            return CardType.TwoPair
        if 2 in lengths:
            return CardType.OnePair
        return CardType.HighCard
    
    def _find_type_joker(self,cards:str) -> CardType:
        try:
            joker_i = cards.index("J") 
        except ValueError:
            return self._find_type(cards)
        
        current_value = CardType.HighCard
        for new_card in [*(valid_card_list())]:
            if new_card == "J":
                continue
            test_cards = list(cards)
            test_cards[joker_i] = new_card
            new_value = self._find_type_joker("".join(test_cards))
            if new_value.value > current_value.value:
                current_value = new_value
        
        return current_value

    
    def sort_string(self):
        v = str(self.type.value) + ":" + "".join(["abcdefghijklmnoZ"[card_value(x)] for x in [*self.cards]])
        return v
    
    def __repr__(self) -> str:
        return f""



def valid_card_list() -> str:
    if rule_jokers_enabled:
        return "J23456789TQKA"
    return "23456789TJQKA"

def card_value(char:chr):
    return valid_card_list().index(char)

def main(line_list: list):
    hand_list = list()
    for l in line_list:
        card,bid = re.split(' +',l)
        hand = Hand(card,bid)
        hand_list.append(hand)
        #print(hand.sort_string())
    
    hand_list.sort(key=lambda x: x.sort_string())
    print(hand_list)

    rank_total = 0
    rank = 1
    for single_hand in hand_list:
        rank_total += rank * single_hand.bid
        rank += 1
    
    print(f"total {rank_total}")

if __name__ == "__main__":
    parser = argparse.ArgumentParser(description="day 1 solver")
    parser.add_argument("-input",type=str)
    parser.add_argument("-part",type=int)
    args = parser.parse_args()

    if args.part == 2:
        rule_jokers_enabled = True

    filename = args.input
    if filename == None:
        parser.print_help()
        exit(1)
    file = open(filename,'r')
    main([line.rstrip('\n') for line in file.readlines()])
    file.close()

[โ€“] [email protected] 2 points 11 months ago* (last edited 11 months ago) (1 children)

I barely registered a difference between part 1 and part 2.

Part 1: 00:00:00.0018302
Part 2: 00:00:00.0073136

I suppose it took about 3.5 times as long, but I didn't notice :P

Edit: I realize that I made the implicit assumption in my solution that it doesn't make sense to have multiple jokers be interpreted as different values. i.e., The hand with the maximum value will have all Jokers interpreted as the same other card. I think that is true though. It worked out for me anyway.

[โ€“] [email protected] 1 points 11 months ago

Yea I was thinking there might be a simplification trick, but also figured "there can't be that many combinations right?" I suspect that was probably an intended optimisation.

[โ€“] [email protected] 1 points 11 months ago* (last edited 11 months ago)

I think one doesn't need to generate all combinations. All combinations using cards already present in the hand should be enough (since a joker can only increase the value of the hand by being grouped with existing cards (since in this game having four of a kind is always better than having any hand with a four of a kind/full house and having 3 is always better than any hand with pairs, and having a pair is better than any card without any cards of the same kind)). This massively decreases the amount of combinations needed to be generated per jokery hand.