this post was submitted on 10 Oct 2023
0 points (50.0% liked)

Lisp

53 readers
2 users here now

founded 1 year ago
MODERATORS
[email protected]
[email protected]
0
Comparison of a counter in racket-scheme and sbcl-lisp (alien.top)
submitted 1 year ago by [email protected] to c/[email protected]
8 comments fedilink hide all child comments
 

A counter in racket-scheme:

#lang typed/racket

(define my-counter!
    (let ([t 0])
        (lambda ()
	        (set! t (+ 1 t))
	    t);lambda
	);let
);define 
(print (my-counter!))
(print (my-counter!))

A counter in sbcl-lisp:

load "~/quicklisp/setup.lisp")

(declaim (optimize (speed 3) (safety 3)))

(let ((c 0))
    (defun my-counter! ()
        (lambda ()
            (setf c (+ 1 c))
	    c); lambda
	 ) ;defun
) ;let

(defun main ()
(print (funcall (my-counter!)))
(print (funcall (my-counter!)))
)

(sb-ext:save-lisp-and-die "test.exe" :toplevel #'main :executable t)

Could someone elaborate why i need "funcall" in lisp and not in scheme ? And why the different placing of let ?

you are viewing a single comment's thread
view the rest of the comments
[–] [email protected] 1 points 1 year ago

You shouldn't need funcall in your common lisp code, but the way you defined your function requires it. You have

(let ((c 0))
  (defun my-counter! ()
    (lambda ()
      (setf c (+ 1 c))
      c)))

defun already defines a function; you don't need to also wrap the function body in a lambda. This definition allows you to avoid the funcall:

(let ((c 0))
  (defun my-counter! ()
    (setf c (+ 1 c))
    c))

Though it's worth knowing that unlike in scheme, common lisp will return the value after a setf. There's also a convenience macro called incf that increments variables so you can write the whole thing like this:

(let ((c 0))
  (defun my-counter! ()
    (incf c)))

And your other question: Why the different placing of the let?

In common lisp, defun, defvar, defparameter, defmacro, ... all affect global scope, no matter where they appear. scheme's define does not affect global scope; its effects are only visible locally. This means that a defun inside of a let body still creates a globally accessible function that closes over the variables defined in the let bindings. Scheme, by contrast, needs to have a define at global level (or at least outside the let) but the function body still needs to close over the let variables.