this post was submitted on 13 Aug 2023
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[–] [email protected] 32 points 1 year ago* (last edited 1 year ago) (3 children)

I'm a little sad nobody has done the correct math and it's been too long for me to do it off the top of my head lol.

A^2+B^2=C^2? What distance are the diagonals if the sides are 6' apart?

6x6 + 6x6 = sqrt72 = 8.49' !

I did it bois. Ty calculator for sqrt72...

[–] [email protected] 25 points 1 year ago (1 children)

Now do the conversion factor from feef to feet!

[–] [email protected] 21 points 1 year ago

The diagonal is 6ft. The side is 6 ft. So 6² + 6feef² = 6²

1 feef = 0ft

[–] [email protected] 5 points 1 year ago (2 children)

Now, what's the length of the sides if the diagonals are 6ft?

[–] [email protected] 5 points 1 year ago* (last edited 1 year ago) (1 children)

Thats easy.
6 * 6 = 36
36 = a² + b²
Lets assume a = b
So a² = 18 = b²
a = b = 4,2426406871

[–] [email protected] 1 points 1 year ago

What if every initial value is unknown?

[–] [email protected] 2 points 1 year ago
[–] [email protected] 2 points 1 year ago

8.49'!~=116699.97'

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