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Seeking help with a curl command in a bash script - SOLVED (lemmy.thewooskeys.com)

submitted 1 week ago* (last edited 1 week ago) by [email protected] to c/[email protected]

23 comments fedilink hide all child comments

I've got this command in a bash script:

TEST=$(curl -o /dev/null -s -k -w "%{http_code}" -u "${USERNAME}:${PASSWORD}" "${URL}/dashboard/")
echo "${TEST}" #debug

When the script runs, the output is "000".

When I run the same curl command from the shell, the output is "200" (which is correct, since the URL is valid).

I verified that the USERNAME, PASSWORD, and URL vars are being passed to the subshell.

I'd appreciate it if you could point out what I'm doing wrong here. :)

UPDATE: This has been solved.

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[–] [email protected] 1 points 1 week ago (1 children)

Try to add -f to ssh command

[–] [email protected] 2 points 1 week ago (1 children)

That seems to have done it!

Running the ssh -f... instead of ssh.... & seems to work first time and every time.

It makes it so SSH_PID=$! doesn't work, but I used pgrep -f <ssh command> instead.

Thanks!

[–] [email protected] 1 points 1 week ago

You are very welcome! That was the hypothesis, that ssh doesn’t go into background as you want it to, since it works for the second run, but tunnel is there after the first.