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Seeking help with a curl command in a bash script - SOLVED (lemmy.thewooskeys.com)

submitted 1 week ago* (last edited 1 week ago) by [email protected] to c/[email protected]

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I've got this command in a bash script:

TEST=$(curl -o /dev/null -s -k -w "%{http_code}" -u "${USERNAME}:${PASSWORD}" "${URL}/dashboard/")
echo "${TEST}" #debug

When the script runs, the output is "000".

When I run the same curl command from the shell, the output is "200" (which is correct, since the URL is valid).

I verified that the USERNAME, PASSWORD, and URL vars are being passed to the subshell.

I'd appreciate it if you could point out what I'm doing wrong here. :)

UPDATE: This has been solved.

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[–] [email protected] 2 points 1 week ago* (last edited 1 week ago) (1 children)

Add echo before your curl command to see what the expanded command line actually is. Perhaps the arguments aren't as you expect them

[–] [email protected] 1 points 1 week ago

Thanks for the suggestion. I already tried this: echo-ed the curl command to stdout and then in the shell copied it and pasted it to run it. From the script I get "000", from the shell I get "200".