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Perchance - Create a Random Text Generator

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⚄︎ Perchance

This is a Lemmy Community for perchance.org, a platform for sharing and creating random text generators.

Feel free to ask for help, share your generators, and start friendly discussions at your leisure :)

This community is mainly for discussions between those who are building generators. For discussions about using generators, especially the popular AI ones, the community-led Casual Perchance forum is likely a more appropriate venue.

See this post for the Complete Guide to Posting Here on the Community!

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1. Please follow the Lemmy.World instance rules.

2. Be kind and friendly.

  • Please be kind to others on this community (and also in general), and remember that for many people Perchance is their first experience with coding. We have members for whom English is not their first language, so please be take that into account too :)

3. Be thankful to those who try to help you.

  • If you ask a question and someone has made a effort to help you out, please remember to be thankful! Even if they don't manage to help you solve your problem - remember that they're spending time out of their day to try to help a stranger :)

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  • See Perchance AI FAQ for FAQ about the AI tools.
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VioneT
perchance
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[Request] .evaluateItem (etc) return "" when all options have 0 odds (self.perchance)
submitted 3 months ago* (last edited 3 months ago) by wthit56 to c/perchance
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Currently it seems to return the first option. I'm working on some UI that allows you to toggle options on and off, by setting the odds. But because of the way it handles this I'm going to have to proxy over it and overwrite the list in the tree... so then I can return "" when there are no possible options. I feel like it would just make sense if it returned an empty string if there are child options but none are possible.

Edit: For all-impossible options, .selectMany() returns the first item multiple times. And .selectUnique() returns each item in order.

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[–] VioneT 1 points 3 months ago (1 children)

Not sure how you have your list (or if you are using a list with dynamic odds) but here is an example to filter options with 0 odds:

random = {0-3}

output
  Selected: [x = random.selectOne] | Output: ~[verb]~ // the ~ are just here to show that it returns a blank string
	
verb
  $output = [this.selectAll.filter(a => a.getOdds)] // returns a blank string if there isn't any option with odds.
  pat^[x == '1']
  befriend^[x == '2']
  help^[x == '3']
[–] wthit56 1 points 3 months ago

Ah I see, that's clever... I've done it another way, as there are other shenanigans I'm up to with lists. But thanks for the idea.

Still makes more sense to me that it just works this way by default, anyhow. Saying an item has a probability of 0 and getting it every time just seems nonsensical in practical terms. ;p