Linux Questions

1170 readers

24 users here now

Linux questions Rules (in addition of the Lemmy.zip rules)

stay on topic
be nice (no name calling)
do not post long blocks of text such as logs
do not delete your posts
only post questions (no information posts)

Tips for giving and receiving help

be as clear and specific
say thank you if a solution works
verify your solutions before posting them as facts.

Any rule violations will result in disciplinary actions

founded 1 year ago

MODERATORS

[email protected]

Seeking help with a curl command in a bash script - SOLVED (lemmy.thewooskeys.com)

submitted 1 week ago* (last edited 1 week ago) by [email protected] to c/[email protected]

23 comments fedilink hide all child comments

I've got this command in a bash script:

TEST=$(curl -o /dev/null -s -k -w "%{http_code}" -u "${USERNAME}:${PASSWORD}" "${URL}/dashboard/")
echo "${TEST}" #debug

When the script runs, the output is "000".

When I run the same curl command from the shell, the output is "200" (which is correct, since the URL is valid).

I verified that the USERNAME, PASSWORD, and URL vars are being passed to the subshell.

I'd appreciate it if you could point out what I'm doing wrong here. :)

UPDATE: This has been solved.

you are viewing a single comment's thread
view the rest of the comments

[–] [email protected] 1 points 1 week ago

I'm not sure how to chain these 2 commands with &&, because the SSH command is being put in the background with &.

This doesn't work:

SSH_CMD="ssh -N -L ${LOCAL_PORT}:127.0.0.1:${REMOTE_PORT} ${REMOTE_USER}@${REMOTE_HOST}"
$SSH_CMD & && TEST=$(curl -o /dev/null -s -k -w "%{http_code}" -u "${USERNAME}:${PASSWORD}" "${URL}/dashboard/")
SSH_PID=$!
SSH_RESULT=$?
echo $TEST

Perhaps I don't need it in the background - the goal was to establish the tunnel and then continue with the script without it hanging until the ssh command is canceled.